Group Theory Problem 1
There is a canonical surjection Q→Q/Z given by q↦q+Z, i.e. ∣Q∣≥∣Q/Z∣. The sets r+Q∈R/Q for r∈R are countable. Additionally, we know that ⋃r∈Rr+Q=R. Because R is not countable, the set R/Q must be uncountably infinite. Otherwise, the countable union of countable sets would be countable. Thus, ∣R/Q∣=∣R∣. In summary:
∣R/Q∣=∣R∣>∣Q∣≥∣Q/Z∣.
This means that there does not exists a bijective function between the two groups.